0=-16t^2-42

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Solution for 0=-16t^2-42 equation: 



0=-16t^2-42

We move all terms to the left:

0-(-16t^2-42)=0

We add all the numbers together, and all the variables

-(-16t^2-42)=0

We get rid of parentheses

16t^2+42=0

a = 16; b = 0; c = +42;
Δ = b2-4ac
Δ = 02-4·16·42
Δ = -2688
Delta is less than zero, so there is no solution for the equation

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